Find a mistake in the following chain of arguments, pretending to prove that 2=1
| 1) | Let a = b |
| 2) | Multiply 1) by a a2 = ab |
| 3) | Add a2 – 2ab to both parts of 2) a2 + a2 – 2ab = ab + a2 – 2ab |
| 4) | 3) could be simplified: 2a2 – 2ab = a2 – ab |
| 5) | It is the same as 2(a2 – ab) = 1(a2 – ab) |
| 6) | Reduce 5) by (a2 – ab). 2=1 |
Mistake is in the 6th step.
We can not divide by (a2 – ab) because a2– ab = 0.
a = b, so a2– ab = 0.


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